Simple Equations Mcqs - Set 1

1)   A bag contains equal number of Rs.5, Rs.2 and Re.1 coins. If the total amount in the bag is Rs.1152, find the number of coins of each kind?

a. 432
b. 288
c. 144
d. 72
e. None of these
Answer  Explanation 

ANSWER: 144

Explanation:
Let the number of coins of each kind be x.
=> 5x + 2x + 1x = 1152
=> 8x = 1152 => x = 144


2)   Arslan and Bilal have some marbles with them. Arslan told Bilal “if you give me ‘x’ marbles, both of us will have equal number of marbles”. Bilal then told Arslan “if you give me twice as many marbles, I will have 30 more marbles than you would”. Find ‘x’?

a. 40
b. 5
c. 6
d. 8
Answer  Explanation 

ANSWER: 5

Explanation:
If Bilal gives ‘x’ marbles to Arslan then Bilal and Arslan would have V – x and A + x marbles.
V – x = A + x — (1)
If Arslan gives 2x marbles to Bilal then Arslan and Bilal would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.


3)   Atif ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 6 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Atif paid the cashier was Rs.961. Find the cost of each ice-cream cup?

a. Rs.25
b. Rs.22.50
c. Rs.20
d. Rs.17.50
e. None of these
Answer  Explanation 

ANSWER: Rs.25

Explanation:
Let the cost of each ice-cream cup be Rs.x
16(6) + 5(45) + 7(70) + 6(x) = 961
96 + 225 + 490 + 6x = 961
6x = 150 => x = 25.


4)   Three consecutive odd integers are in increasing order such that the sum of the last two integers is 13 more than the first integer. Find the three integers?

a. 9, 11, 13
b. 11, 13, 15
c. 13, 15, 17
d. 7, 9, 11
e. None of these
Answer  Explanation 

ANSWER: 7, 9, 11

Explanation:
Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.
x + 4 + x + 2 = x + 13 => x = 7
Hence three consecutive odd integers are 7, 9 and 11.


5)   There are some rabbits and peacocks in a zoo. The total number of their heads is 60 and total number of their legs is 192. Find the number of total rabbits?

a. 30
b. 46
c. 40
d. 44
e. None of these
Answer  Explanation 

ANSWER: None of these

Explanation:
Let the number of rabbits and peacocks be ‘r’ and ‘p’ respectively. As each animal has only one head, so r + p = 60 — (1)
Each rabbit has 4 legs and each peacock has 2 legs. Total number of legs of rabbits and peacocks, 4r + 2p = 192 — (2)
Multiplying equation (1) by 2 and subtracting it from equation (2), we get
=> 2r = 72 => r = 36.


6)   On the independence day, bananas were be equally distributed among the children in a school so that each child would get two bananas. On the particular day 360 children were absent and as a result each child got two extra bananas. Find the actual number of children in the school?

a. 600
b. 620
c. 500
d. 520
e. None of these
Answer  Explanation 

ANSWER: None of these

Explanation:
Let the number of children in the school be x. Since each child gets 2 bananas, total number of bananas = 2x.
2x/(x – 360) = 2 + 2(extra)
=> 2x – 720 = x => x = 720.


7)   Eight years ago, Zahid’s age was 4/3 times that of Shahid. Eight years hence, Zahid’s age will be 6/5 times that of Shahid. What is the present age of Zahid?

a. 30 years
b. 40 years
c. 32 years
d. 48 years
e. None of these
Answer  Explanation 

ANSWER: 40 years

Explanation:
Let the present ages of Zahid and Shahid be ‘Z’ and ‘S’ years respectively.
Z – 8 = 4/3 (S – 8) and Z + 8 = 6/5 (S + 8)
3/4(Z – 8) = S – 8 and 5/6(Z + 8) = S + 8
S = 3/4 (Z – 8) + 8 = 5/6 (Z + 8) – 8
=> 3/4 Z – 6 + 8 = 5/6 Z + 20/3 – 8
=> 10 – 20/3 = 10/12 Z – 9/12 Z
=> 10/3 = Z/12 => Z = 40.


8)   Rs.1200 divided among P, Q and R. P gets half of the total amount received by Q and R. Q gets one-third of the total amount received by P and R. Find the amount received by R?

a. Rs.400
b. Rs.500
c. Rs.300
d. Rs.600
e. None of these
Answer  Explanation 

ANSWER: Rs.500

Explanation:
Let the amounts to be received by P, Q and R be p, q and r.
p + q + r = 1200
p = 1/2 (q + r) => 2p = q + r
Adding ‘p’ both sides, 3p = p + q + r = 1200
=> p = Rs.400
q = 1/3 (p + r) => 3q = p + r
Adding ‘q’ both sides, 4q = p + q + r = 1200
=> q = Rs.300
r = 1200 – (p + q) => r = Rs.500.


9)   P, Q and R have Rs.6000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?

a. Rs.3000
b. Rs.3600
c. Rs.2400
d. Rs.4000
e. None of these
Answer  Explanation 

ANSWER: Rs.2400

Explanation:
Let the amount with R be Rs.r
r = 2/3 (total amount with P and Q)
r = 2/3(6000 – r) => 3r = 12000 – 2r
=> 5r = 12000 => r = 2400.


10)   A bag contains a total of 93 coins in the form of one rupee and 50 paise coins. If the total value of coins in the bag is Rs.56, find the number of 50 paise coins in the bag?

a. 60
b. 56
c. 64
d. 74
e. None of these
Answer  Explanation 

ANSWER: 74

Explanation:
Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74