Percentage Mcqs - Set 3

1)   A period of 4 hrs 30 min is what percent of a day?

a. 18 3/4 %
b. 20 %
c. 16 3/4 %
d. 19 %
Answer  Explanation 

ANSWER: 18 3/4 %

Explanation:
Required % = (9/48 × 100)% = 75/4 % = 18 ¾ %


2)   When a number is first increased by 10 % and then reduced by 10 % the number:__________?

a. does not change
b. decreased by 1 %
c. increased by 1 %
d. None of these
Answer  Explanation 

ANSWER: decreased by 1 %

Explanation:
Let the given number be x

Increased Number = (110% of x)

= (110/100 × x) = (11x/10)

Finally reduced number = (90 % of 11x/10)

= (90/100 × 11x/10) = 99x/100

Decrease = (x – 99x/100) = x/100

Decrease % = (x/100 × 1/x × 100)% = 1 %


3)   Two number is first increased by 10 % and then reduced by 10 % the number:__________?

a. 2:5
b. 4:5
c. 6:7
d. 3:5
Answer  Explanation 

ANSWER: 4:5

Explanation:
Let the third number be x.

Then 1st number = 120% of x = (120/100 × x) = 6x/5

2nd number = 150 % of x = (150/100 × x) = 3x/2

Ratio of these numbers = 6x/5 : 3x/2 = 12: 15 = 4 : 5


4)   If the side of a square is increased by 25 %. Then its area is increased by:__________?

a. 25 %
b. 55%
c. 40.5 %
d. 56.25 %
Answer  Explanation 

ANSWER: 56.25 %

Explanation:
Let the side of the square be x units.

Then it’s area = x2 sq. Units

Side of new square = 125 % of x = (125/100 × x)units = 5x/4 units

New area = (5x/4 × 5x/4)sq.units = 25×2/16 Sq.units

Increase in area = (25×2/16 – x2) = 9×2/16 Sq.Units

Increase % = (9×2/16 × 1/x2 × 100)%

= 225/4 % = 56.25 %


5)   A typist uses a paper 30 cm by 15 cm. He leaves a margin of 2.5 cm at the top as well as at the bottom and 1.25 cm on either side. What percentage of paper area is approximately available for typing?

a. 65 %
b. 70 %
c. 80 %
d. 60%
Answer  Explanation 

ANSWER: 70 %

Explanation:
Total Area of the Paper = (30 × 15) Sq.cm = 450 Sq.cm

Area Used = [(30-5)×(15-2.5) ]Sq.cm

= (25 × 12.5) Sq.cm = (25 x 25/2) Sq.cm = 625/2 cm2

Percentage are Used by = (625/2× 1/450×100) %

= 69.4 % = 70 % nearly


6)   The length of a rectangle is increased by 10 % and breadth decreased by 10 % Then the area of a new rectangle is:_________?

a. neither increased nor decreased
b. increased by 1 %
c. decreased by 1 %
d. decreased by 10 %
Answer  Explanation 

ANSWER: decreased by 1 %

Explanation:
Let original length = l units and original breadth = b units

Then original Area = lb sq. Units

New length = (110/100 l) units = (11 l)/10 units

New breadth = (90/100 b) units = (9 l)/10 units

New area = (11l/10 × 9b/10) sq. Units = 99lb/100 sq. units

Decrease in area = (lb- 99lb/100)sq units = lb/100 sq. units

Decrease in area = (lb/100 × 1/lb ×100) % = 1 %

Decrease by = 1 %


7)   A and B are two fixed points 5 cm apart and c is a point on AB such that AC = 3 cm. If the length of AC is increased by 6 % the length of CB is decreased by:_________?

a. 6 %
b. 7 %
c. 8 %
d. 9 %
Answer  Explanation 

ANSWER: 9 %

Explanation:
AC = 3cm, CB = (5 – 3)cm = 2 cm

New length AC = 106 % of 3 cm

= (106/100 ×3) cm = 3.18 cm.

New length CB = (5 – 3.18) cm = 1.82 cm

CB Decreased on 2cm = (2 – 1.82)cm = 0.18cm

CB Decrease % = (0.18/2 ×100) % = 9 %


8)   5 % of the income of A is equal to 15 % of the income of B and 10 % of the income of B is equal to 20 % of the income of c. If the income of C is Rs. 2000. What is the total income of A, B and C?

a. Rs. 14000
b. Rs 16000
c. Rs. 18000
d. Rs. 12400
Answer  Explanation 

ANSWER: Rs. 18000

Explanation:
10/100 × B = 20/100 × c

=>B = 2c =>B = (2 × 2000) = 4000

5/100 × A = 5/100 × B =>A = 3B = (3 × 4000) = 12000

(A + B + C) = Rs (12000 + 4000 + 2000) = Rs. 18000


9)   A reduction of 20 % in the price of sugar enables a purchaser to obtain 3kg more for Rs. 120. The original price of sugar per kg is:________?

a. Rs. 15
b. Rs. 12
c. Rs. 10
d. Rs. 8
Answer  Explanation 

ANSWER: Rs. 10

Explanation:
No explanation is available for this question!


10)   In 50 gm alloy of gold and silver the gold is 80 % by weight. How much gold should be mixed with this alloy so that the weight of gold would become 95 %?

a. 200 gm
b. 150 gm
c. 50 gm
d. 10 gm
Answer  Explanation 

ANSWER: 150 gm

Explanation:
No explanation is available for this question!


11)   The ratio of the number of boys and girls is 3:2 if 20 % of the boys and 30 % of the girls are scholarship holders then the percentage of students who do not get scholarship is_________?

a. 50
b. 72
c. 75
d. 76
Answer  Explanation 

ANSWER: 76

Explanation:
Let the number of boys be 3x and number of girls be 2x.

Number of scholarship holders

= (20/100 ×3x+ 30/100 ×2x) = 6x/5

Number of those who do not hold scholarship

= (5x- 6x/5) = 19x/5

Required percentage = (19x/5 × 1/5x ×100) % = 76 %


12)   Out of an earning of Rs. 720 Ram spends 65 %. How much does he save?

a. Rs. 350
b. Rs. 390
c. Rs. 252
d. Rs. 316
Answer  Explanation 

ANSWER: Rs. 252

Explanation:
Savings % = (100 – 65) % = 35 %

Saving = 35 % of Rs. 720

= Rs(35/100 ×720) = Rs. 252


13)   In an examination, 65 % of the total examinees passed if the number of failures is 420, the total number of examinees is:_________?

a. 500
b. 1200
c. 1000
d. 1625
Answer  Explanation 

ANSWER: 1200

Explanation:
Percentage of failure = (100 – 65) % = 35 %

Let the total number of examinees be x.

Then 35 % of x = 420

=> 35/100 × x = 420

=> x =(420 × 100/35) = 1200


14)   Rs. 395 are divided among A, B and C ins such a manner that B gets 25 % more than A and 20 % more than C. The share of A is:

a. Rs. 198
b. Rs. 120
c. Rs. 180
d. Rs. 195
Answer  Explanation 

ANSWER: Rs. 120

Explanation:
Suppose A gets Rs. x.

Then B gets 125 % of x = 125/100 × x = Rs. 5x/4

If B gets Rs. 120.

Then c gets Rs. 100

If B gets Rs 5x/4, then c gets = Rs (100/120 ×5x/4)

= Rs 25x/24 x + 5x/4 + 25x/24 = 395

=> (24x + 30x + 25x) = (395 × 24)

=>79x = (395 × 24)

= > x = ((395 ×24)/79) = 120

Hence, A gets Rs. 120


15)   605 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20 % of the total number of children. How many sweets did each child receive?

a. 11
b. 24
c. 45
d. cannot be determined
Answer  Explanation 

ANSWER: 11

Explanation:
Let the total number of children be x.

Then x × 20/100 × x = 605

=> x2 = 3025

=> x = √3025 = 55

Number of sweets received by each child

= (20/100 ×55) = 11


16)   Two numbers are less than q third number by 30 % and 37 % respectively. How much percent is the second number less than the first?

a. 10 %
b. 15 %
c. 20 %
d. 25 %
Answer  Explanation 

ANSWER: 10 %

Explanation:
Let the 3rd number be 100.

Then 1st number = 70,

2nd number = 63

2nd number is less than 1st by = (7/70 ×100) % = 10 %


17)   The length of a rectangle is increased by 60 %. By what percent would the width have to be decreased to maintain the same area?

a. 37 ½ %
b. 60 %
c. 75 %
d. none of these
Answer  Explanation 

ANSWER: 37 ½ %

Explanation:
Let length = 100 m.

Breath = 100 m.

New length = 160 m.

New breath = x meters

Then, = 160 × x = 100 × 100

(or) X = (100 ×100)/160 × 125/2

Decrease in breadth = (100- 125/2) % = 37 ½ %


18)   If the side of a square is increased by 30 %. Its area is increased by:_________?

a. 9 %
b. 30 %
c. 60 %
d. 69 %
Answer  Explanation 

ANSWER: 69 %

Explanation:
Let, side = 100cm.

Area = (100 × 100) cm2 = 10000 cm2

New area = (130 × 130) cm2 = 16900 cm2

Increase in area = (6900/10000 ×100) % = 69 %


19)   The price of an article has been reduced by 25 %. In order to restore the original price, the new price must be increased by:________?

a. 33 1/3 %
b. 11 1/9 %
c. 9 1/11 %
d. 66 2/3 %
Answer  Explanation 

ANSWER: 33 1/3 %

Explanation:
Let original price = Rs. 100.

Reduced Price = Rs. 75.

Increase on Rs. 75 = Rs. 25

Increase on 100 = (25/75 x 100) % = 33 1/3 %


20)   p is six times as large as q. The percent that q is less than p is:________?

a. 83 1/3
b. 16 2/3
c. 90
d. 60
Answer  Explanation 

ANSWER: 83 1/3

Explanation:
p = 6q.

Thus, q is less than p by 5q

q is less than p by (5q/6q x 100)% = 83 1/3 %