Problems on LCM & HCF Mcqs


Q.  In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are______?

a. 700,400
b. 820,360
c. 800,500
d. 820,369


ANSWER: See Answer
 
No explanation is available for this question!
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MCQs:  The smallest fraction, which each of 6/7, 5/14, 10/21 will divide exactly is_________?
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MCQs:  The H.C.F of two numbers is 8. Which of the following can never be their L.C.M?
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